3.427 \(\int \frac{c+d x+e x^2+f x^3+g x^4+h x^5}{x^2 (a+b x^3)^3} \, dx\)

Optimal. Leaf size=362 \[ -\frac{\log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (a^{2/3} (a h+5 b e)+2 b^{2/3} (7 b c-a f)\right )}{54 a^{10/3} b^{4/3}}+\frac{\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (a^{2/3} (a h+5 b e)+2 b^{2/3} (7 b c-a f)\right )}{27 a^{10/3} b^{4/3}}+\frac{\tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right ) \left (-5 a^{2/3} b e+a^{5/3} (-h)-2 a b^{2/3} f+14 b^{5/3} c\right )}{9 \sqrt{3} a^{10/3} b^{4/3}}+\frac{x \left (-2 b x (5 b c-2 a f)-3 b x^2 (3 b d-a g)+a (a h+5 b e)\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{x \left (-b x (b c-a f)-b x^2 (b d-a g)+a (b e-a h)\right )}{6 a^2 b \left (a+b x^3\right )^2}-\frac{d \log \left (a+b x^3\right )}{3 a^3}-\frac{c}{a^3 x}+\frac{d \log (x)}{a^3} \]

[Out]

-(c/(a^3*x)) + (x*(a*(b*e - a*h) - b*(b*c - a*f)*x - b*(b*d - a*g)*x^2))/(6*a^2*b*(a + b*x^3)^2) + (x*(a*(5*b*
e + a*h) - 2*b*(5*b*c - 2*a*f)*x - 3*b*(3*b*d - a*g)*x^2))/(18*a^3*b*(a + b*x^3)) + ((14*b^(5/3)*c - 5*a^(2/3)
*b*e - 2*a*b^(2/3)*f - a^(5/3)*h)*ArcTan[(a^(1/3) - 2*b^(1/3)*x)/(Sqrt[3]*a^(1/3))])/(9*Sqrt[3]*a^(10/3)*b^(4/
3)) + (d*Log[x])/a^3 + ((2*b^(2/3)*(7*b*c - a*f) + a^(2/3)*(5*b*e + a*h))*Log[a^(1/3) + b^(1/3)*x])/(27*a^(10/
3)*b^(4/3)) - ((2*b^(2/3)*(7*b*c - a*f) + a^(2/3)*(5*b*e + a*h))*Log[a^(2/3) - a^(1/3)*b^(1/3)*x + b^(2/3)*x^2
])/(54*a^(10/3)*b^(4/3)) - (d*Log[a + b*x^3])/(3*a^3)

________________________________________________________________________________________

Rubi [A]  time = 0.829961, antiderivative size = 362, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 10, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.263, Rules used = {1829, 1834, 1871, 1860, 31, 634, 617, 204, 628, 260} \[ -\frac{\log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (a^{2/3} (a h+5 b e)+2 b^{2/3} (7 b c-a f)\right )}{54 a^{10/3} b^{4/3}}+\frac{\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (a^{2/3} (a h+5 b e)+2 b^{2/3} (7 b c-a f)\right )}{27 a^{10/3} b^{4/3}}+\frac{\tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right ) \left (-5 a^{2/3} b e+a^{5/3} (-h)-2 a b^{2/3} f+14 b^{5/3} c\right )}{9 \sqrt{3} a^{10/3} b^{4/3}}+\frac{x \left (-2 b x (5 b c-2 a f)-3 b x^2 (3 b d-a g)+a (a h+5 b e)\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{x \left (-b x (b c-a f)-b x^2 (b d-a g)+a (b e-a h)\right )}{6 a^2 b \left (a+b x^3\right )^2}-\frac{d \log \left (a+b x^3\right )}{3 a^3}-\frac{c}{a^3 x}+\frac{d \log (x)}{a^3} \]

Antiderivative was successfully verified.

[In]

Int[(c + d*x + e*x^2 + f*x^3 + g*x^4 + h*x^5)/(x^2*(a + b*x^3)^3),x]

[Out]

-(c/(a^3*x)) + (x*(a*(b*e - a*h) - b*(b*c - a*f)*x - b*(b*d - a*g)*x^2))/(6*a^2*b*(a + b*x^3)^2) + (x*(a*(5*b*
e + a*h) - 2*b*(5*b*c - 2*a*f)*x - 3*b*(3*b*d - a*g)*x^2))/(18*a^3*b*(a + b*x^3)) + ((14*b^(5/3)*c - 5*a^(2/3)
*b*e - 2*a*b^(2/3)*f - a^(5/3)*h)*ArcTan[(a^(1/3) - 2*b^(1/3)*x)/(Sqrt[3]*a^(1/3))])/(9*Sqrt[3]*a^(10/3)*b^(4/
3)) + (d*Log[x])/a^3 + ((2*b^(2/3)*(7*b*c - a*f) + a^(2/3)*(5*b*e + a*h))*Log[a^(1/3) + b^(1/3)*x])/(27*a^(10/
3)*b^(4/3)) - ((2*b^(2/3)*(7*b*c - a*f) + a^(2/3)*(5*b*e + a*h))*Log[a^(2/3) - a^(1/3)*b^(1/3)*x + b^(2/3)*x^2
])/(54*a^(10/3)*b^(4/3)) - (d*Log[a + b*x^3])/(3*a^3)

Rule 1829

Int[(Pq_)*(x_)^(m_)*((a_) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> With[{q = Expon[Pq, x]}, Module[{Q = Polynomi
alQuotient[a*b^(Floor[(q - 1)/n] + 1)*x^m*Pq, a + b*x^n, x], R = PolynomialRemainder[a*b^(Floor[(q - 1)/n] + 1
)*x^m*Pq, a + b*x^n, x], i}, Dist[1/(a*n*(p + 1)*b^(Floor[(q - 1)/n] + 1)), Int[x^m*(a + b*x^n)^(p + 1)*Expand
ToSum[(n*(p + 1)*Q)/x^m + Sum[((n*(p + 1) + i + 1)*Coeff[R, x, i]*x^(i - m))/a, {i, 0, n - 1}], x], x], x] - S
imp[(x*R*(a + b*x^n)^(p + 1))/(a^2*n*(p + 1)*b^(Floor[(q - 1)/n] + 1)), x]]] /; FreeQ[{a, b}, x] && PolyQ[Pq,
x] && IGtQ[n, 0] && LtQ[p, -1] && ILtQ[m, 0]

Rule 1834

Int[((Pq_)*((c_.)*(x_))^(m_.))/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Int[ExpandIntegrand[((c*x)^m*Pq)/(a + b*
x^n), x], x] /; FreeQ[{a, b, c, m}, x] && PolyQ[Pq, x] && IntegerQ[n] &&  !IGtQ[m, 0]

Rule 1871

Int[(P2_)/((a_) + (b_.)*(x_)^3), x_Symbol] :> With[{A = Coeff[P2, x, 0], B = Coeff[P2, x, 1], C = Coeff[P2, x,
2]}, Int[(A + B*x)/(a + b*x^3), x] + Dist[C, Int[x^2/(a + b*x^3), x], x] /; EqQ[a*B^3 - b*A^3, 0] ||  !Ration
alQ[a/b]] /; FreeQ[{a, b}, x] && PolyQ[P2, x, 2]

Rule 1860

Int[((A_) + (B_.)*(x_))/((a_) + (b_.)*(x_)^3), x_Symbol] :> With[{r = Numerator[Rt[a/b, 3]], s = Denominator[R
t[a/b, 3]]}, -Dist[(r*(B*r - A*s))/(3*a*s), Int[1/(r + s*x), x], x] + Dist[r/(3*a*s), Int[(r*(B*r + 2*A*s) + s
*(B*r - A*s)*x)/(r^2 - r*s*x + s^2*x^2), x], x]] /; FreeQ[{a, b, A, B}, x] && NeQ[a*B^3 - b*A^3, 0] && PosQ[a/
b]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 634

Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[(2*c*d - b*e)/(2*c), Int[1/(a +
b*x + c*x^2), x], x] + Dist[e/(2*c), Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] &
& NeQ[2*c*d - b*e, 0] && NeQ[b^2 - 4*a*c, 0] &&  !NiceSqrtQ[b^2 - 4*a*c]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 260

Int[(x_)^(m_.)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[Log[RemoveContent[a + b*x^n, x]]/(b*n), x] /; FreeQ
[{a, b, m, n}, x] && EqQ[m, n - 1]

Rubi steps

\begin{align*} \int \frac{c+d x+e x^2+f x^3+g x^4+h x^5}{x^2 \left (a+b x^3\right )^3} \, dx &=\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}-\frac{\int \frac{-6 b^2 c-6 b^2 d x-b (5 b e+a h) x^2+4 b^2 \left (\frac{b c}{a}-f\right ) x^3+3 b^2 \left (\frac{b d}{a}-g\right ) x^4}{x^2 \left (a+b x^3\right )^2} \, dx}{6 a b^2}\\ &=\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}+\frac{x \left (a (5 b e+a h)-2 b (5 b c-2 a f) x-3 b (3 b d-a g) x^2\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{\int \frac{18 b^4 c+18 b^4 d x+2 b^3 (5 b e+a h) x^2-2 b^4 \left (\frac{5 b c}{a}-2 f\right ) x^3}{x^2 \left (a+b x^3\right )} \, dx}{18 a^2 b^4}\\ &=\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}+\frac{x \left (a (5 b e+a h)-2 b (5 b c-2 a f) x-3 b (3 b d-a g) x^2\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{\int \left (\frac{18 b^4 c}{a x^2}+\frac{18 b^4 d}{a x}+\frac{2 b^3 \left (a (5 b e+a h)-2 b (7 b c-a f) x-9 b^2 d x^2\right )}{a \left (a+b x^3\right )}\right ) \, dx}{18 a^2 b^4}\\ &=-\frac{c}{a^3 x}+\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}+\frac{x \left (a (5 b e+a h)-2 b (5 b c-2 a f) x-3 b (3 b d-a g) x^2\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{d \log (x)}{a^3}+\frac{\int \frac{a (5 b e+a h)-2 b (7 b c-a f) x-9 b^2 d x^2}{a+b x^3} \, dx}{9 a^3 b}\\ &=-\frac{c}{a^3 x}+\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}+\frac{x \left (a (5 b e+a h)-2 b (5 b c-2 a f) x-3 b (3 b d-a g) x^2\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{d \log (x)}{a^3}+\frac{\int \frac{a (5 b e+a h)-2 b (7 b c-a f) x}{a+b x^3} \, dx}{9 a^3 b}-\frac{(b d) \int \frac{x^2}{a+b x^3} \, dx}{a^3}\\ &=-\frac{c}{a^3 x}+\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}+\frac{x \left (a (5 b e+a h)-2 b (5 b c-2 a f) x-3 b (3 b d-a g) x^2\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{d \log (x)}{a^3}-\frac{d \log \left (a+b x^3\right )}{3 a^3}+\frac{\int \frac{\sqrt [3]{a} \left (-2 \sqrt [3]{a} b (7 b c-a f)+2 a \sqrt [3]{b} (5 b e+a h)\right )+\sqrt [3]{b} \left (-2 \sqrt [3]{a} b (7 b c-a f)-a \sqrt [3]{b} (5 b e+a h)\right ) x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{27 a^{11/3} b^{4/3}}+\frac{\left (2 b^{2/3} (7 b c-a f)+a^{2/3} (5 b e+a h)\right ) \int \frac{1}{\sqrt [3]{a}+\sqrt [3]{b} x} \, dx}{27 a^{10/3} b}\\ &=-\frac{c}{a^3 x}+\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}+\frac{x \left (a (5 b e+a h)-2 b (5 b c-2 a f) x-3 b (3 b d-a g) x^2\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{d \log (x)}{a^3}+\frac{\left (2 b^{2/3} (7 b c-a f)+a^{2/3} (5 b e+a h)\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{27 a^{10/3} b^{4/3}}-\frac{d \log \left (a+b x^3\right )}{3 a^3}-\frac{\left (14 b^{5/3} c-5 a^{2/3} b e-2 a b^{2/3} f-a^{5/3} h\right ) \int \frac{1}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{18 a^3 b}-\frac{\left (2 b^{2/3} (7 b c-a f)+a^{2/3} (5 b e+a h)\right ) \int \frac{-\sqrt [3]{a} \sqrt [3]{b}+2 b^{2/3} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{54 a^{10/3} b^{4/3}}\\ &=-\frac{c}{a^3 x}+\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}+\frac{x \left (a (5 b e+a h)-2 b (5 b c-2 a f) x-3 b (3 b d-a g) x^2\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{d \log (x)}{a^3}+\frac{\left (2 b^{2/3} (7 b c-a f)+a^{2/3} (5 b e+a h)\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{27 a^{10/3} b^{4/3}}-\frac{\left (2 b^{2/3} (7 b c-a f)+a^{2/3} (5 b e+a h)\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{54 a^{10/3} b^{4/3}}-\frac{d \log \left (a+b x^3\right )}{3 a^3}-\frac{\left (14 b^{5/3} c-5 a^{2/3} b e-2 a b^{2/3} f-a^{5/3} h\right ) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1-\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a}}\right )}{9 a^{10/3} b^{4/3}}\\ &=-\frac{c}{a^3 x}+\frac{x \left (a (b e-a h)-b (b c-a f) x-b (b d-a g) x^2\right )}{6 a^2 b \left (a+b x^3\right )^2}+\frac{x \left (a (5 b e+a h)-2 b (5 b c-2 a f) x-3 b (3 b d-a g) x^2\right )}{18 a^3 b \left (a+b x^3\right )}+\frac{\left (14 b^{5/3} c-5 a^{2/3} b e-2 a b^{2/3} f-a^{5/3} h\right ) \tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right )}{9 \sqrt{3} a^{10/3} b^{4/3}}+\frac{d \log (x)}{a^3}+\frac{\left (2 b^{2/3} (7 b c-a f)+a^{2/3} (5 b e+a h)\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{27 a^{10/3} b^{4/3}}-\frac{\left (2 b^{2/3} (7 b c-a f)+a^{2/3} (5 b e+a h)\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{54 a^{10/3} b^{4/3}}-\frac{d \log \left (a+b x^3\right )}{3 a^3}\\ \end{align*}

Mathematica [A]  time = 0.569985, size = 336, normalized size = 0.93 \[ -\frac{\frac{9 a^2 \left (a^2 (g+h x)-a b (d+x (e+f x))+b^2 c x^2\right )}{b \left (a+b x^3\right )^2}-\frac{3 a \left (a^2 h x+a b (6 d+x (5 e+4 f x))-10 b^2 c x^2\right )}{b \left (a+b x^3\right )}+\frac{a^{2/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (5 a^{2/3} b e+a^{5/3} h-2 a b^{2/3} f+14 b^{5/3} c\right )}{b^{4/3}}-\frac{2 a^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (5 a^{2/3} b e+a^{5/3} h-2 a b^{2/3} f+14 b^{5/3} c\right )}{b^{4/3}}+\frac{2 \sqrt{3} a^{2/3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt{3}}\right ) \left (5 a^{2/3} b e+a^{5/3} h+2 a b^{2/3} f-14 b^{5/3} c\right )}{b^{4/3}}+18 a d \log \left (a+b x^3\right )+\frac{54 a c}{x}-54 a d \log (x)}{54 a^4} \]

Antiderivative was successfully verified.

[In]

Integrate[(c + d*x + e*x^2 + f*x^3 + g*x^4 + h*x^5)/(x^2*(a + b*x^3)^3),x]

[Out]

-((54*a*c)/x + (9*a^2*(b^2*c*x^2 + a^2*(g + h*x) - a*b*(d + x*(e + f*x))))/(b*(a + b*x^3)^2) - (3*a*(a^2*h*x -
10*b^2*c*x^2 + a*b*(6*d + x*(5*e + 4*f*x))))/(b*(a + b*x^3)) + (2*Sqrt[3]*a^(2/3)*(-14*b^(5/3)*c + 5*a^(2/3)*
b*e + 2*a*b^(2/3)*f + a^(5/3)*h)*ArcTan[(1 - (2*b^(1/3)*x)/a^(1/3))/Sqrt[3]])/b^(4/3) - 54*a*d*Log[x] - (2*a^(
2/3)*(14*b^(5/3)*c + 5*a^(2/3)*b*e - 2*a*b^(2/3)*f + a^(5/3)*h)*Log[a^(1/3) + b^(1/3)*x])/b^(4/3) + (a^(2/3)*(
14*b^(5/3)*c + 5*a^(2/3)*b*e - 2*a*b^(2/3)*f + a^(5/3)*h)*Log[a^(2/3) - a^(1/3)*b^(1/3)*x + b^(2/3)*x^2])/b^(4
/3) + 18*a*d*Log[a + b*x^3])/(54*a^4)

________________________________________________________________________________________

Maple [B]  time = 0.016, size = 622, normalized size = 1.7 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((h*x^5+g*x^4+f*x^3+e*x^2+d*x+c)/x^2/(b*x^3+a)^3,x)

[Out]

1/27/a/b^2/(1/b*a)^(2/3)*3^(1/2)*arctan(1/3*3^(1/2)*(2/(1/b*a)^(1/3)*x-1))*h+14/27/a^3/(1/b*a)^(1/3)*ln(x+(1/b
*a)^(1/3))*c-7/27/a^3/(1/b*a)^(1/3)*ln(x^2-(1/b*a)^(1/3)*x+(1/b*a)^(2/3))*c+d*ln(x)/a^3-1/3*d*ln(b*x^3+a)/a^3-
5/9/a^3/(b*x^3+a)^2*b^2*x^5*c+5/18/a^2/(b*x^3+a)^2*x^4*b*e+2/9/a^2/(b*x^3+a)^2*x^5*b*f-5/54/a^2/b/(1/b*a)^(2/3
)*ln(x^2-(1/b*a)^(1/3)*x+(1/b*a)^(2/3))*e-c/a^3/x+5/27/a^2/b/(1/b*a)^(2/3)*3^(1/2)*arctan(1/3*3^(1/2)*(2/(1/b*
a)^(1/3)*x-1))*e+5/27/a^2/b/(1/b*a)^(2/3)*ln(x+(1/b*a)^(1/3))*e-2/27/a^2*f/b/(1/b*a)^(1/3)*ln(x+(1/b*a)^(1/3))
+1/27/a^2*f/b/(1/b*a)^(1/3)*ln(x^2-(1/b*a)^(1/3)*x+(1/b*a)^(2/3))+7/18/a/(b*x^3+a)^2*x^2*f-1/9/(b*x^3+a)^2/b*x
*h+1/18/a/(b*x^3+a)^2*x^4*h-1/6/(b*x^3+a)^2/b*g+4/9/a/(b*x^3+a)^2*x*e+1/2/a/(b*x^3+a)^2*d-14/27/a^3*3^(1/2)/(1
/b*a)^(1/3)*arctan(1/3*3^(1/2)*(2/(1/b*a)^(1/3)*x-1))*c-13/18/a^2/(b*x^3+a)^2*b*x^2*c+2/27/a^2*f*3^(1/2)/b/(1/
b*a)^(1/3)*arctan(1/3*3^(1/2)*(2/(1/b*a)^(1/3)*x-1))-1/54/a/b^2/(1/b*a)^(2/3)*ln(x^2-(1/b*a)^(1/3)*x+(1/b*a)^(
2/3))*h+1/27/a/b^2/(1/b*a)^(2/3)*ln(x+(1/b*a)^(1/3))*h+1/3/a^2/(b*x^3+a)^2*b*d*x^3

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((h*x^5+g*x^4+f*x^3+e*x^2+d*x+c)/x^2/(b*x^3+a)^3,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((h*x^5+g*x^4+f*x^3+e*x^2+d*x+c)/x^2/(b*x^3+a)^3,x, algorithm="fricas")

[Out]

Timed out

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((h*x**5+g*x**4+f*x**3+e*x**2+d*x+c)/x**2/(b*x**3+a)**3,x)

[Out]

Timed out

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Giac [A]  time = 1.09166, size = 556, normalized size = 1.54 \begin{align*} -\frac{d \log \left ({\left | b x^{3} + a \right |}\right )}{3 \, a^{3}} + \frac{d \log \left ({\left | x \right |}\right )}{a^{3}} + \frac{\sqrt{3}{\left (\left (-a b^{2}\right )^{\frac{1}{3}} a^{2} h + 5 \, \left (-a b^{2}\right )^{\frac{1}{3}} a b e + 14 \, \left (-a b^{2}\right )^{\frac{2}{3}} b c - 2 \, \left (-a b^{2}\right )^{\frac{2}{3}} a f\right )} \arctan \left (\frac{\sqrt{3}{\left (2 \, x + \left (-\frac{a}{b}\right )^{\frac{1}{3}}\right )}}{3 \, \left (-\frac{a}{b}\right )^{\frac{1}{3}}}\right )}{27 \, a^{4} b^{2}} + \frac{{\left (\left (-a b^{2}\right )^{\frac{1}{3}} a^{2} h + 5 \, \left (-a b^{2}\right )^{\frac{1}{3}} a b e - 14 \, \left (-a b^{2}\right )^{\frac{2}{3}} b c + 2 \, \left (-a b^{2}\right )^{\frac{2}{3}} a f\right )} \log \left (x^{2} + x \left (-\frac{a}{b}\right )^{\frac{1}{3}} + \left (-\frac{a}{b}\right )^{\frac{2}{3}}\right )}{54 \, a^{4} b^{2}} + \frac{6 \, a b^{2} d x^{4} - 4 \,{\left (7 \, b^{3} c - a b^{2} f\right )} x^{6} +{\left (a^{2} b h + 5 \, a b^{2} e\right )} x^{5} - 18 \, a^{2} b c - 7 \,{\left (7 \, a b^{2} c - a^{2} b f\right )} x^{3} - 2 \,{\left (a^{3} h - 4 \, a^{2} b e\right )} x^{2} + 3 \,{\left (3 \, a^{2} b d - a^{3} g\right )} x}{18 \,{\left (b x^{3} + a\right )}^{2} a^{3} b x} + \frac{{\left (14 \, a^{3} b^{4} c \left (-\frac{a}{b}\right )^{\frac{1}{3}} - 2 \, a^{4} b^{3} f \left (-\frac{a}{b}\right )^{\frac{1}{3}} - a^{5} b^{2} h - 5 \, a^{4} b^{3} e\right )} \left (-\frac{a}{b}\right )^{\frac{1}{3}} \log \left ({\left | x - \left (-\frac{a}{b}\right )^{\frac{1}{3}} \right |}\right )}{27 \, a^{7} b^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((h*x^5+g*x^4+f*x^3+e*x^2+d*x+c)/x^2/(b*x^3+a)^3,x, algorithm="giac")

[Out]

-1/3*d*log(abs(b*x^3 + a))/a^3 + d*log(abs(x))/a^3 + 1/27*sqrt(3)*((-a*b^2)^(1/3)*a^2*h + 5*(-a*b^2)^(1/3)*a*b
*e + 14*(-a*b^2)^(2/3)*b*c - 2*(-a*b^2)^(2/3)*a*f)*arctan(1/3*sqrt(3)*(2*x + (-a/b)^(1/3))/(-a/b)^(1/3))/(a^4*
b^2) + 1/54*((-a*b^2)^(1/3)*a^2*h + 5*(-a*b^2)^(1/3)*a*b*e - 14*(-a*b^2)^(2/3)*b*c + 2*(-a*b^2)^(2/3)*a*f)*log
(x^2 + x*(-a/b)^(1/3) + (-a/b)^(2/3))/(a^4*b^2) + 1/18*(6*a*b^2*d*x^4 - 4*(7*b^3*c - a*b^2*f)*x^6 + (a^2*b*h +
5*a*b^2*e)*x^5 - 18*a^2*b*c - 7*(7*a*b^2*c - a^2*b*f)*x^3 - 2*(a^3*h - 4*a^2*b*e)*x^2 + 3*(3*a^2*b*d - a^3*g)
*x)/((b*x^3 + a)^2*a^3*b*x) + 1/27*(14*a^3*b^4*c*(-a/b)^(1/3) - 2*a^4*b^3*f*(-a/b)^(1/3) - a^5*b^2*h - 5*a^4*b
^3*e)*(-a/b)^(1/3)*log(abs(x - (-a/b)^(1/3)))/(a^7*b^3)